Playing with Digits in Java

Here you are given with an Integer, you need to display the count of non-repeated integers starting from 1 to till that number.

	import java.util.*;
	public class PlayingWithDigits {
	public static int playingWithDigits(int input1)
	{
	int output1=0,output2=0,output=0,count=0;
	for(int k=1;k<=input1;k++){
	if(k<100){
	if(k%11==0){
	count++; //with in 100 we can divide it with 11, to get repeated counts.
	}
	output1=count;
	}else{
	String x=String.valueOf(k);
	char [] c=x.toCharArray();
	for(int i=0,j=i+1;i<c.length && j<c.length;i++,j++){
	String y=String.valueOf(c[i]);
	String z=String.valueOf(c[j]);
	if(y.equals(z)){
	count=1; //here we are converting integer to string so that checking repeated values will be easy.
	break; //if digits is repeated, then it breaks the loop.
	}else{
	count=0; //if digits is not repeated then counter is zero.
	}
	}
	output2+=count; //now we are saving counts of repeated values.
	}
	}
	output=output1+output2; //combining repeated counts as one.
	int finalOutput=input1-output; //finally we need to show output as non-repeated so we are subtracting with input repeated counts.
	return finalOutput;
	}
	public static void main (String [] args){
	Scanner in = new Scanner(System.in);
	int output = 0;
	int ip1 = Integer.parseInt(in.nextLine().trim());
	output = playingWithDigits(ip1);
	System.out.println(String.valueOf(output));
	in.close();
	}
	}

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Input
7
Output: 7 as there are no repeated counts from 1 to 7.

similarly
Input : 100

Output: 10 (11,22,33,44,55,66,77,88,99,100 these are the repeated  digit counts from 1 to 100).