Sort 5 multiples in ascending order using java

For this challenge, you will be given an array and you are asked to find multiples of 5 in the given array, sort and put them first in the array. Rest all the elements will preserve their orders. 


Input Format - 
you will be taking a number as an input from STDIN which tells about the length of the array. On another line, array elements should be there with single space between them. 

Output Format - 
print the required array to the STDOUT. 

	import java.util.*;
	public class Testing2 {
	public static void main(String [] args){
	Scanner sc=new Scanner(System.in);
	int size;
	size=sc.nextInt();
	int [] arr=new int [size];
	int sorted[]=new int[size]; //sorted array created to preserve non 5 multiples in the same order.
	for(int i=0;i<size;i++){
	arr[i]=sc.nextInt();
	sorted[i]=arr[i];
	}
	Arrays.sort(sorted); //sorted array a backup array to save 5 multiples in ascending order
	int arr2 []=new int[size]; //final array created
	int k=0;
	for(int a=0;a<sorted.length;a++){
	if(sorted[a]%5==0){
	arr2[k]=sorted[a]; //saving 5 multiples in final array.
	k++;
	}
	}
	for(int g=0;g<arr2.length;g++){
	if(arr[g]%5!=0){ //saving non 5 multiples in final array
	arr2[k]=arr[g];
	k++;
	}
	System.out.print(arr2[g]+" ");
	}
	sc.close();
	}
	}

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Sample Test Case: 
Sample Input:-6
9 14 15 10 8 5
Sample Output - 
5 10 15 9 14 8