Second to smaller and larger in java

You will be given an array and you need to find the second largest and second smallest numbers and add them. 

Note: the length of the array should not be less than 2. 


Input Format - 
you will be taking a number as an input from stdin which tells about the length of the array. On another line, array elements should be there with single space between them. 

Output Format - 
you need to print the addition of second largest and second smallest elements to the stdout. 

	/*
	* You will be given an array and you need to find the second largest and second smallest numbers and add them.
	*Note: the length of the array should not be less than 2.
	*/
	import java.io.*;
	import java.util.*;
	public class CandidateCode {
	public static void main(String args[] ) throws Exception {
	Scanner sc=new Scanner(System.in);
	int size;
	size=sc.nextInt();
	int [] arr=new int [size];
	for(int i=0;i<size;i++){
	arr[i]=sc.nextInt();
	}
	int max=arr[0],secondMax=0,min=arr[1],secondMin=0;
	for(int j=0;j<arr.length;j++){
	if(arr[j]>max){
	secondMax=max;
	max=arr[j];
	}else if(arr[j]<min){
	secondMin=min;
	min=arr[j];
	}else if(arr[j]<secondMin){
	secondMin=arr[j];
	}else if(arr[j]>secondMax){
	secondMax=arr[j];
	}
	}
	System.out.println(secondMax+secondMin);
	sc.close();
	}
	}

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Sample Test Case: 
Sample Input:-7
48 77 7 11 49 99 78
Sample Output - 
89